42 47 58 74 271 | The 47-year-old who killed the Sikh police officer on the Jesuit birthday, September 27, 2019

42 47 58 74 271 | The 47-year-old who killed the Sikh police officer on the Jesuit birthday, September 27, 2019 Hello people in the world, today Random Find Truth will provide information about the correctness and important updated opinions that you must read with the title 42 47 58 74 271 | The 47-year-old who killed the Sikh police officer on the Jesuit birthday, September 27, 2019 that has been Random Find Truth analysis, search and prepare well for you to read all. Hopefully information from Random Find Truth about Articles Find Truth, the Random Find Truth write you can make us all human beings who are knowledgeable and blessed for all.

Title : 42 47 58 74 271 | The 47-year-old who killed the Sikh police officer on the Jesuit birthday, September 27, 2019
Link : 42 47 58 74 271 | The 47-year-old who killed the Sikh police officer on the Jesuit birthday, September 27, 2019




https://www.nbcnews.com/news/us-news/convict-accused-killing-sikh-texas-deputy-will-likely-face-death-n1060386

A 47-year-old?  He killed a Sikh?




Cop = 47; Policeman = 47; Government = 47; Authority = 47; News = 47

And notice his surname, Solis, summing to 74.


Notice the emphasis above on 'trailblazer'.


Masonic = 74; Killing = 74; Occult = 74



https://www.npr.org/2019/09/29/765417200/sikh-deputy-trailblazer-fatally-shot-in-houston-area-traffic-stop


Notice how his name sums to 271.



This news emerged on September 28, the 271st day of the year.


https://www.cnn.com/2019/09/28/us/texas-sikh-deputy-shot-saturday/index.html




Notice, he was 42-years-old.




The killing occurred on September 27, the Jesuit formation date.



42 47 58 74 271 | The 47-year-old who killed the Sikh police officer on the Jesuit birthday, September 27, 2019

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42 47 58 74 271 | The 47-year-old who killed the Sikh police officer on the Jesuit birthday, September 27, 2019


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